Important Python Concept

[Solved] Unexpected EOF while parsing in Python

Hey there!
In this article, we’ll be talking about unexpected EOF while parsing in Python. We’ll also talk about how
these errors can be prevented and corrected.
 


SyntaxError: unexpected EOF while parsing

 

SyntaxError: unexpected EOF while parsing is an error that occurs when the end of your source code has been
reached even before all the code blocks have been completed.
Generally, it can be due to some part of unfinished code which thus further leads to the occurrence of errors
even before the execution of code altogether.
In short, some mistake in the syntax or formation of a specific block of code can lead to this.

 

Main Causes of Unexpected EOF while parsing in Python

 

You get an error if Python comes to the end of file (EOF) even before going through each block of code
The main causes are:
1. Too many or missing many parentheses.
2. Missing of a special line of code in loops, try-except, or if-else statements.
3. Undefined parameters.
4. Missing of colons.
5. And the most common, indentation errors.

 

Example 1: Too many parentheses

 

The example will lead to errors as if you see carefully, many curly brackets have been added to the dictionary in
the very first line thus, leading to errors.

dictionary = {{{"item1" : "pen", "iten2": "rose", "item3": "ice cream"}}}
dictionary["item4"] = "book"
dictionary.pop("item1")
print(dictionary)
view raw eof_1.py hosted with ❤ by GitHub

 

Example 2: Missing parentheses

 

Similarly, missing parenthesis can also lead to SyntaxError as in the case of the above example where the
the square bracket after the last element of the list is missing.

list = ["USA", "UK", "Spain", "India", "Portugal", "Bangladesh", "Brazil"
print(list)
view raw eof_2.py hosted with ❤ by GitHub

 

Example 3: Indentation Errors

 

In this example, there is an indentation error in the case of the print statement.
Therefore, make sure to add some space before the print statement in case of if-else.

if a==2:
print("a is 2")
elif a==3:
print("a is 3")
elif a==4:
print("a is 4")
else:
print("I don't know")
view raw eof_3.py hosted with ❤ by GitHub

 

Conclusion

 

Avoiding some common errors can lead to a syntax-free code. So make sure your code is free from indentation errors,
undefined parameters, missing colons and parenthesis and you’ll be good to go:)

In this python tutorial, we learned about unexpected EOF while parsing in Python.
I hope this article helped you.

In case the solution is not clear to you, I suggest you take a live 1:1 lesson on this subject from me. I am an Oracle-certified tutor who would love to teach this stuff to you.
Aniket Malik

 
Aniket Malik

Aniket Malik

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